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View Compilation Error

0_0_4409744_5926\Main.java:1: 非法字符: \35
#include<stdio.h>
^
0_0_4409744_5926\Main.java:2: 非法字符: \35
#include<math.h>
^
0_0_4409744_5926\Main.java:6: 需要为 class、interface 或 enum
void sieve_fib()
^
0_0_4409744_5926\Main.java:9: 需要为 class、interface 或 enum
	fib[0] = 1;
	^
0_0_4409744_5926\Main.java:10: 需要为 class、interface 或 enum
	fib[1] = 2;
	^
0_0_4409744_5926\Main.java:11: 需要为 class、interface 或 enum
	double m; 
	^
0_0_4409744_5926\Main.java:12: 需要为 class、interface 或 enum
	m = pow(2.0,31.0);
	^
0_0_4409744_5926\Main.java:13: 需要为 class、interface 或 enum
	i = 2;
	^
0_0_4409744_5926\Main.java:14: 需要为 class、interface 或 enum
    while(fib[i-1]<m)
    ^
0_0_4409744_5926\Main.java:17: 需要为 class、interface 或 enum
		i++;
		^
0_0_4409744_5926\Main.java:18: 需要为 class、interface 或 enum
	}
	^
0_0_4409744_5926\Main.java:25: 需要为 class、interface 或 enum
	sieve_fib();
	^
0_0_4409744_5926\Main.java:27: 需要为 class、interface 或 enum
	while(scanf("%d",&n),n)
	^
0_0_4409744_5926\Main.java:30: 需要为 class、interface 或 enum
		for(i=0;fib[i]<=n;i++)
		^
0_0_4409744_5926\Main.java:30: 需要为 class、interface 或 enum
		for(i=0;fib[i]<=n;i++)
		        ^
0_0_4409744_5926\Main.java:30: 需要为 class、interface 或 enum
		for(i=0;fib[i]<=n;i++)
		                  ^
0_0_4409744_5926\Main.java:35: 需要为 class、interface 或 enum
				break;
				^
0_0_4409744_5926\Main.java:36: 需要为 class、interface 或 enum
			}
			^
0_0_4409744_5926\Main.java:41: 需要为 class、interface 或 enum
        if(k%2==0 && k!=-1)
        ^
0_0_4409744_5926\Main.java:43: 需要为 class、interface 或 enum
		if(k%2!=0 && k!=-1)
		^
0_0_4409744_5926\Main.java:45: 需要为 class、interface 或 enum
	}
	^
0_0_4409744_5926\Main.java:47: 需要为 class、interface 或 enum
}


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