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View Compilation Error

0_0_39781381_24408.cpp
VC2013\INCLUDE\xstddef(328) : error C2338: The C++ Standard doesn't provide a hash for this type.
        VC2013\INCLUDE\type_traits(572): 参见对正在编译的类 模板 实例化“std::hash<_Kty>”的引用
        with
        [
            _Kty=std::tuple<int,int,int>
        ]
        VC2013\INCLUDE\xhash(196): 参见对正在编译的类 模板 实例化“std::is_empty<_Hasher>”的引用
        with
        [
            _Hasher=std::hash<std::tuple<int,int,int>>
        ]
        VC2013\INCLUDE\xhash(220): 参见对正在编译的类 模板 实例化“std::_Hash_oper2<false,_Hasher,_Keyeq>”的引用
        with
        [
            _Hasher=std::hash<std::tuple<int,int,int>>
,            _Keyeq=std::equal_to<std::tuple<int,int,int>>
        ]
        VC2013\INCLUDE\unordered_map(23): 参见对正在编译的类 模板 实例化“std::_Uhash_compare<_Kty,_Hasher,_Keyeq>”的引用
        with
        [
            _Kty=std::tuple<int,int,int>
,            _Hasher=std::hash<std::tuple<int,int,int>>
,            _Keyeq=std::equal_to<std::tuple<int,int,int>>
        ]
        VC2013\INCLUDE\xhash(255): 参见对正在编译的类 模板 实例化“std::_Umap_traits<_Kty,_Ty,std::_Uhash_compare<_Kty,_Hasher,_Keyeq>,_Alloc,false>”的引用
        with
        [
            _Kty=std::tuple<int,int,int>
,            _Ty=int
,            _Hasher=std::hash<std::tuple<int,int,int>>
,            _Keyeq=std::equal_to<std::tuple<int,int,int>>
,            _Alloc=std::allocator<std::pair<const std::tuple<int,int,int>,int>>
        ]
        VC2013\INCLUDE\unordered_map(81): 参见对正在编译的类 模板 实例化“std::_Hash<std::_Umap_traits<_Kty,_Ty,std::_Uhash_compare<_Kty,_Hasher,_Keyeq>,_Alloc,false>>”的引用
        with
        [
            _Kty=std::tuple<int,int,int>
,            _Ty=int
,            _Hasher=std::hash<std::tuple<int,int,int>>
,            _Keyeq=std::equal_to<std::tuple<int,int,int>>
,            _Alloc=std::allocator<std::pair<const std::tuple<int,int,int>,int>>
        ]
        0_0_39781381_24408.cpp(8): 参见对正在编译的类 模板 实例化“std::unordered_map<std::tuple<int,int,int>,int,std::hash<_Kty>,std::equal_to<_Kty>,std::allocator<std::pair<const _Kty,_Ty>>>”的引用
        with
        [
            _Kty=std::tuple<int,int,int>
,            _Ty=int
        ]


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