F.A.Q
Hand In Hand
Online Acmers
Problem Archive
Realtime Judge Status
Authors Ranklist
 
     C/C++/Java Exams     
ACM Steps
Go to Job
Contest LiveCast
ICPC@China
Best Coder beta
VIP | STD Contests
    DIY | Web-DIY beta
Author ID 
Password 
 Register new ID

Ponds

Time Limit: 1500/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)
Total Submission(s): 6650    Accepted Submission(s): 1835


Problem Description
Betty owns a lot of ponds, some of them are connected with other ponds by pipes, and there will not be more than one pipe between two ponds. Each pond has a value $v$.

Now Betty wants to remove some ponds because she does not have enough money. But each time when she removes a pond, she can only remove the ponds which are connected with less than two ponds, or the pond will explode.

Note that Betty should keep removing ponds until no more ponds can be removed. After that, please help her calculate the sum of the value for each connected component consisting of a odd number of ponds
 

Input
The first line of input will contain a number $T (1 \leq T \leq 30)$ which is the number of test cases.

For each test case, the first line contains two number separated by a blank. One is the number $p (1 \leq p \leq 10^4)$ which represents the number of ponds she owns, and the other is the number $m (1 \leq m \leq 10^5)$ which represents the number of pipes.

The next line contains $p$ numbers $v_1, . . . , v_p$, where $v_i (1 \leq v_i \leq 10^8)$ indicating the value of pond $i$.

Each of the last $m$ lines contain two numbers $a$ and $b$, which indicates that pond $a$ and pond $b$ are connected by a pipe.
 

Output
For each test case, output the sum of the value of all connected components consisting of odd number of ponds after removing all the ponds connected with less than two pipes.
 

Sample Input
1 7 7 1 2 3 4 5 6 7 1 4 1 5 4 5 2 3 2 6 3 6 2 7
 

Sample Output
21
 

Source
 

Statistic | Submit | Discuss | Note
Hangzhou Dianzi University Online Judge 3.0
Copyright © 2005-2024 HDU ACM Team. All Rights Reserved.
Designer & Developer : Wang Rongtao LinLe GaoJie GanLu
Total 0.000000(s) query 1, Server time : 2024-11-22 07:14:46, Gzip enabled