ZZX and Permutations

ZZX likes permutations.

ZZX knows that a permutation can be decomposed into disjoint cycles(see https://en.wikipedia.org/wiki/Permutation#Cycle_notation). For example:
145632=(1)(35)(462)=(462)(1)(35)=(35)(1)(462)=(246)(1)(53)=(624)(1)(53)……
Note that there are many ways to rewrite it, but they are all equivalent.
A cycle with only one element is also written in the decomposition, like (1) in the example above.

Now, we remove all the parentheses in the decomposition. So the decomposition of 145632 can be 135462,462135,351462,246153,624153……

Now you are given the decomposition of a permutation after removing all the parentheses (itself is also a permutation). You should recover the original permutation. There are many ways to recover, so you should find the one with largest lexicographic order.

First line contains an integer $t$, the number of test cases.
Then $t$ testcases follow. In each testcase:
First line contains an integer $n$, the size of the permutation.
Second line contains $n$ space-separated integers, the decomposition after removing parentheses.

$n\le 10^5$. There are 10 testcases satisfying $n\le 10^5$, 200 testcases satisfying $n\le 1000$.

Output $n$ space-separated numbers in a line for each testcase.
Don't output space after the last number of a line.

2
6
1 4 5 6 3 2
2
1 2

4 6 2 5 1 3
2 1

XJZX

2015 Multi-University Training Contest 4