|
||||||||||
MophuesTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 327670/327670 K (Java/Others)Total Submission(s): 3278 Accepted Submission(s): 1396 Problem Description As we know, any positive integer C ( C >= 2 ) can be written as the multiply of some prime numbers: C = p1¡Áp2¡Á p3¡Á ... ¡Á pk which p1, p2 ... pk are all prime numbers.For example, if C = 24, then: 24 = 2 ¡Á 2 ¡Á 2 ¡Á 3 here, p1 = p2 = p3 = 2, p4 = 3, k = 4 Given two integers P and C. if k<=P( k is the number of C's prime factors), we call C a lucky number of P. Now, XXX needs to count the number of pairs (a, b), which 1<=a<=n , 1<=b<=m, and gcd(a,b) is a lucky number of a given P ( "gcd" means "greatest common divisor"). Please note that we define 1 as lucky number of any non-negative integers because 1 has no prime factor. Input The first line of input is an integer Q meaning that there are Q test cases. Then Q lines follow, each line is a test case and each test case contains three non-negative numbers: n, m and P (n, m, P <= 5¡Á105. Q <=5000). Output For each test case, print the number of pairs (a, b), which 1<=a<=n , 1<=b<=m, and gcd(a,b) is a lucky number of P. Sample Input
Sample Output
Source | ||||||||||
|