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Dice

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)
Total Submission(s): 452    Accepted Submission(s): 281


Problem Description
Given a normal dice (with 1, 2, 3, 4, 5, 6 on each face), we define:
F(N) to be the expected number of tosses until we have a number facing up for N consecutive times.
H(N) to be the expected number of tosses until we have the number '1' facing up for N consecutive times.
G(M) to be the expected number of tosses until we have the number '1' facing up for M times.
Given N, you are supposed to calculate the minimal M1 that G (M1) >= F (N) and the minimal M2 that G(M2)>=H(N)
 

Input
The input contains multiple cases.
Each case has a positive integer N in a separated line. (1<=N<=1000000000)
The input is terminated by a line containing a single 0.
 

Output
For each case, output the minimal M1 and M2 as required in a single line, separated by a single space.
Since the answer could be very large, you should output the answer mod 2011 instead.
 

Sample Input
1 2 0
 

Sample Output
1 1 2 7
 

Source
 

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