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Fibonacci

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)
Total Submission(s): 494    Accepted Submission(s): 182


Problem Description
We know the Fibonacci Sequence

F1=1,F2=1,F3=2,F4=3,F5=5,

...

Fx = Fx-1+Fx-2

We want to know the Mth number which has K consecutive "0" at the end of Fx.

For example,

F15=610

It is the first number which has only one "0" at the end.

F300=222232244629420445529739893461909967206666939096499764990979600.

It is the second number which has two "0" at the end.

Of course, the Fx may be very large if M and K are big. So we only want to know the subscript of Fx (it means the "x" For a given M and K)
 

Input
Input includes multiple cases.

First line is the number of case x

The next x lines: Each line contains two integer number, K and M, divided by a space.
 

Output
For each case:

Print a integer number in a line, is the Mth number which has K consecutive 0s at the end of Fx. (You can believe the answer is smaller than 2^31);
 

Sample Input
3 1 1 2 2 2 5
 

Sample Output
15 300 900
 

Source
 

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