|
||||||||||
FibonacciTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 494 Accepted Submission(s): 182 Problem Description We know the Fibonacci Sequence F1=1,F2=1,F3=2,F4=3,F5=5, ... Fx = Fx-1+Fx-2 We want to know the Mth number which has K consecutive "0" at the end of Fx. For example, F15=610 It is the first number which has only one "0" at the end. F300=222232244629420445529739893461909967206666939096499764990979600. It is the second number which has two "0" at the end. Of course, the Fx may be very large if M and K are big. So we only want to know the subscript of Fx (it means the "x" For a given M and K) Input Input includes multiple cases. First line is the number of case x The next x lines: Each line contains two integer number, K and M, divided by a space. Output For each case: Print a integer number in a line, is the Mth number which has K consecutive 0s at the end of Fx. (You can believe the answer is smaller than 2^31); Sample Input
Sample Output
Source | ||||||||||
|