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Hex Factorial

Time Limit: 5000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 858    Accepted Submission(s): 348


Problem Description
The expression N!, reads as the factorial of N, denoting the product of the first N positive integers. If the factorial of N is written in hexadecimal without leading zeros, can you tell us how many zeros are there in it? Take 15! as an example, you should answer "3" because (15)10! = (13077775800)16, and there are 3 zeros in it.
 

Input
The input contains several cases. Each case has one line containing a non-negative decimal integer N (N ¡Ü 100). You need to count the zeros in N! in hexadecimal. A negative number terminates the input.
 

Output
For each non-negative integer N, output one line containing exactly one integer, indicating the number of
zeros in N!.
 

Sample Input
1 15 -1
 

Sample Output
0 3
 

Source
 

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