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DFSTime Limit: 5000/2000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 11621 Accepted Submission(s): 6998 Problem Description A DFS(digital factorial sum) number is found by summing the factorial of every digit of a positive integer. For example ,consider the positive integer 145 = 1!+4!+5!, so it's a DFS number. Now you should find out all the DFS numbers in the range of int( [1, 2147483647] ). There is no input for this problem. Output all the DFS numbers in increasing order. The first 2 lines of the output are shown below. Input no input Output Output all the DFS number in increasing order. Sample Output
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